Problem :-
Call Apex method on click of Enter button
Solution :-
We can use the "keyCode==13" with actionfuction to call the apex method on Enter Key event like below
Apex Class
public with sharing class EnterSearchController {
public string strKey {get;set;}
public List<Account> lstAccount {get;set;}
public EnterSearchController()
{
lstAccount = new List<Account>();
}
public pageReference cancel()
{
return new pageReference('/001/o');
}
public void search()
{
if( strKey != null && strKey !='' )
{
String wildcard = '%'+strKey+'%';
lstAccount = [select id,name from account where name like :wildcard ] ;
}
}
}
<apex:page controller="EnterSearchController" >
<apex:form >
<apex:pageBlock >
<apex:actionFunction action="{!search}" name="actionFunction" />
<apex:pageBlockSection >
<apex:inputText value="{!strKey}" onkeydown="if(event.keyCode==13){this.blur();actionFunction();}" />
</apex:pageBlockSection>
<apex:pageBlockButtons >
<apex:commandButton action="{!cancel}" value="cancel" />
<apex:commandButton action="{!search}" value="Search" />
</apex:pageBlockButtons>
<apex:pageBlockSection columns="1" >
<apex:pageBlockTable value="{!lstAccount }" var="acc">
<apex:column value="{!acc.name}"/>
</apex:pageBlockTable>
</apex:pageBlockSection>
</apex:pageBlock>
</apex:form>
</apex:page>
Other Related Link
1) http://developer.force.com/cookbook/recipe/submit-a-form-with-the-enter-key
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